Abanana plantation is located next to a desert. george, the plantation owner must transport the bananas to market by camel across a 1000 mile stretch of desert. gorge has only one camel. the camel carries a maximum of 1000 bananas at any one time, and it eats one banana for every mile it travels. the plantation produced 3000. what is the greatest number of bananas that can be delivered to market, and how can it be done?

500

Step-by-step explanation:

Assume camel stays at the market after complete delivery.

Idea is to drop off some bananas between the plantation and the market.  Refrigeration is required to avoid bananas going bad!

Status (planatation, 250 mile point, 500 mile point, market)

First trip with 1000 bananas, stop at 250 miles, drop off 500 bananas, and come back to plantation.  (status:  2000, 500, 0, 0) camel ate 500 bananas.

Second trip with 1000 bananas, stop at 250 miles, pick up 250 (to make 1000), drop off 250 at 500 mile point, come back to plantation.  (Status: 1000, 250,250,0) Camel ate 1500 bananas.

Last trip with 1000 bananas, stop at 250 miles, fill-up 250 (total 1000), stop at 500 miles, fill-up to make total 1000.  Travel all the way to market with 500 left.

(Status: 0,0,0,500) Camel ate 500+1000+1000.

Net delivery: 500 bananas to market.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

29933333.33

step-by-step explanation: