Mathematics, 06.07.2019 09:30 dontcare95
How to find the derivative of y=1/x-2
Answers: 1
![y=\dfrac{1}{x-2}=(x-2)^{-1}\\\\\text{use}\ (x^n)'=nx^{n-1}\ and\ f'(g(x))=f'(g(x))\cdot g'(x)\\\\y'=\left[(x-2)^{-1}\right]'=-1(x-2)^{-2}\cdot(x-2)'=-(x-2)^{-2}\cdot1=-\dfrac{1}{(x-2)^2}](/tpl/images/0057/4208/d627e.png)
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