Him wants to run 1800 miles this year, and he plans to run at least 6 miles per day. if jim has already run 720 miles so far this year, what is the maximum number of days that it will take him to run the remaining miles?

Step-by-step explanation:

Write and solve an inequality for d, the # of days:

720 mi + (6 mi / day)d ≥ 1800 mi.  Then:

(6 mi/day)d ≥ 1800 mi - 720 mi, or (6 mi/day)d ≥ 1080 mi.

Solving for d, we get 1080/6 days:  180 days.  If he runs 6 miles per day for 180 days, he will have covered 1800 miles.  His running more days will, of course, increase the total number of miles covered.

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

the correct option is b

step-by-step explanation: