The length of a rectangle is 5 cm more than its width and the area is 50cm2 find the legth, width, and the perimeter

Let the Width be x cm

Then the length which is 5cm more than width must be (x+5) cm

Using the formula for the area = length* width

x(x+5) =50

      (Distribute x on the parenthesis )

     (subtract 50 )

         (Factor)

we get

                     (Not x=-10 because negative side length not possible)

Width = 5 cm

Length = 5+5= 10 cm

Perimeter = 2(Length + width)

So

Perimeter = 2(10+5)

Perimeter = 2*15=30 cm

the length of a rectangle is 5 cm more than its width and the area is 50cm2 find the length, width, and the perimeter

L = W + 5 (5 cm more than its width)

Area = W * L

Substitute Area = 50 and L =  W + 5

50 = W ( W+5)

Distributive property

50 = W^2 + 5W

Subtract 50 from both sides

0 = W^2 + 5W - 50

Re-write

W^2 + 5W - 50 = 0

Factor

(W + 10)(W - 5) = 0

W + 10 = 0; W = -10

W - 5 = 0; W = 5

Dimension cannot be negative so W = 5 cm

L = 5 + 5 = 10 cm

Double check: A = 5 x 10 = 50 cm^2

Perimeter = 2(L + W)

Perimeter = 2(5 + 10)

Perimeter = 2(15)

Perimeter = 30 cm

Answer

L = 10 cm

W = 5 cm

P = 30 cm

Hope that helps

answer: what in the world is this

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.