Find the area of a rectangle with length (2x + 3) and width (x - 4). a) 2x2 - 11x - 12 b) 2x2 - 5x + 12 c) 2x2 + 11x + 12 d) 2x2 - 5x - 12

D

area of a rectangle = length × width

area = (2x + 3)(x - 4) ( expand using FOIL )

       = 2x² - 8x + 3x - 12 = 2x² - 5x - 12 → D

option (a)

step-by-step explanation:

step 1:   take 2 number whose product equal to 25..

and sum of those two number are -10

step: 2 for example here if we take 5,5 are the number,,

5*5=25

and

5+5=10

but we need -10

so if we take   -5,-5

so -5*-5=25

and -5+(-5)=-10

s0

come the equation

replace -10x by these number

like -5x -5x+25

take common

x(x-5)-5(x-5)=0

(x-5)(x-5)=0

this "question" looks more like a project is there any other info you can give me about this. it could be too complex for someone else to do on this website