Charles has rolled a 6-sided die three times and it landed on 3 each time. what is the probability of getting a 3 on the 4th roll? answer choices: a) 1, b) , c) , d)

The answer would be D - 1/6

This is because there are six sides to the die and just because he rolled all 3s before it does not mean he has a better chance to roll a 3 now.

Since there is only 1 3 on the six sided die there is a 1/6 chance he would roll a 3.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?