Abag of marbles contains 7 red, 5 blue, 4 green, and 2 yellow marbles. jon selects a marble, replaces it, then selects another marble. what is the probability that jon selects a red marble and then a yellow marble?

about 0.0432 or 4.32%

Step-by-step explanation:

Given : A bag of marbles contains 7 red, 5 blue, 4 green, and 2 yellow marbles.

Total marbles = 7+5+4+2=18

Let R : Event of getting first marble as red .

Y= Event of getting second marble as yellow.

Jon selects a marble, replaces it, then selects another marble.

⇒Both events are independent .

Probability of getting first marble as red =

Probability of getting second marble as yellow =

Now, the probability that Jon selects a red marble and then a yellow marble :

 [ ∵ Event R and Y are independent .]

Hence, the probability that Jon selects a red marble and then a yellow marble is about 0.0432 or 4.32%.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1