Which functions have graphs that are less steep than the graph of f(x)=2x2 ? select each correct answer. m(x)=3x2 g(x)=−3x2 h(x)=−2x2 k(x)=x2 j(x)=−x2

k(x) = x^2 and j(x) = -x^2

Step-by-step explanation:

The higher the coefficient, the steeper the graph. So the ones that work have to be less than 2.

It can't be 3x^2 because 3 is greater than 2x^2.

It can't be -3x^2 because -3 is the same as 3 except on the other side of the graph, and 3 is greater than 2.

It can't be -2x^2 because it has equal steepness as 2x^2, except it's on the opposite side of the graph.

It is x^2 because 1 is less than 2 in 2x^2, so it's less steep.

It is -x^2 because -1 is the same as 1 except on the other side of the graph, and 1 is less than 2.

Hope this helps!

all it means is function 3

damm bro the struggle

step-by-step explanation: