Will give brainliest plz ! which line is a graph of the equation: 2x + 5y = 10? number graph ranging from negative five to five on the x axis and negative six to two on the y axis. four lines are drawn in blue on the graph. lines a and c have a positive slope and are parallel to each other. lines b and d have a negative slope and are parallel to each other. lines a and b intersect at (zero, two), and lines c and d intersect at (zero, negative two). a. line a b. line b c. line c d. line d

The equation is of line "b"

Step-by-step explanation:

First we find the slope of the given line by using slope intercept form.

Converting the equation into slope intercept form

Divide both side by 5 we get

On comparing with

We get slope

as the slope of line is negative therefore the line will be either line "b" or line "d"

As line "b" pass from (0,2)

On putting point in given equation we get

Which is equal to RHS of the line

Therefore the given equation is of line "b"

Now putting point (0,-2)

We get

Which is not equal to RHS and therefore line "d" is not the required line

Therefore the given equation is of line "b"

i dont know i just need points

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3