Determine the number of real solutions each quadratic equation has. y = 12x2 - 9x + 4 solution(s) 10x + y = -x2 + 2 solution(s) 4y - 7 = 5x2 - x + 2 + 3y real solution(s) y = (-x + 4)2 solution(s)

Answer and Explanation :

Given : Quadratic equations.

To find : Determine the number of real solutions each quadratic equation has.

Solution :

To determine the number of solution of quadratic equation we find the discriminant.

If the quadratic has one real solution.

If the quadratic has no real solution.

If the quadratic has two real solution.

Now, We find one by one

1)

a=12 , b=-9 , c=4

has zero real solution(s).

2)

a=-1 , b=-10 , c=2

has two real solution(s).

3)

a=5 , b=-1 , c=9

has zero real solution(s).

4)

a=1 , b=-8 , c=16

has one real solution(s).

no

two

no

one

just did on edg and got it right

correct answers below:

i think the answer is b