The number of cubic feet of water in a curved container can be approximated by v = 0.95h2.9. find the amount of water in the container when h = 8 feet. round to the nearest tenth.

395.1

Step-by-step explanation:

Simplify  

0.95 ( 8 ) ^2.9= v

395.07956558

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9