Prove that the diagonals of a rectangle bisect each other. plan: since midpoints will be involved, use multiples of __ to name the coordinates for b, c, and d.

To prove diagonals of a rectangle bisect each other.

It is always better to take multiple of 2.

For example A(0,0), B( 2 x,0), C(2 x, 4 x), D(0,4 x).where x is any integer.

as,⇒ AB=CD, and BC=AD,[opposite sides are equal]

⇒ Diagonal AC=Diagonal BD

⇒Sides are perpendicular to one another.

So ABCD is a rectangle.

Mid point of AC=

                     =(x,2 x)

Mid point of B D=

                       =(x,2x)

Which shows that diagonals of rectangle bisect each other.

If you will take all vertices as a multiple of 6 that will be excellent.

i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)