Graph the function f(x)=x2. plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first.

Graph

quadratic function is of the form

In our f(x) there is no x term and constant so we put 0

The value of a=1 , b=0  and c=0

To find vertex , use formula

Plug in the values

=0

Now plug in x=0 in f(x) equation

=0

So vertex is (0,0)

Now we pick some number for x below and above 0

Make a table

x            y=x^2

-2           4

0             0

2            4

Now plot all the points (-2,4) (0,0) and (2,4)

The graph is attached below

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.