The angles in a triangle are such that one angle is 78 degrees more than the smallest angle, while the third angle is 4 times as large as the smallest angle. find the measures of all three angles.

Let the angles are x, y and z.

Let the smallest angle is x

one angle is 78 degrees more than the smallest angle.⇒ y = x + 78 → (1)

the third angle is 4 times as large as the smallest angle. ⇒ z = 4 x → (2)

we should know that the sum of the angles of the triangle = 180°

∴ x + y + z = 180 →(3)

substitute from (1) and (2) at (3)

∴ x + ( x +78) + (4x) = 180

∴ 6x = 180 - 78 = 102

∴ x = 102 ÷ 6 = 17°

∴ y = 17 + 78 = 95°

∴ z = 4x = 68°

So, the measures of all three angles are 17°, 95° and 68°

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

what graph

step-by-step explanation: