For g(x) = 4x-9 find g(x) when x=3 and when x=5 i need again i don't get this one either!

Hey there!

Let's first solve g(x) when x = 3.

The first step is to change wherever it says x in the equation to 3, because that is the value we are solving for.

g(3) = 4(3) - 9

Next, we can multiply 4 by 3, because multiplication comes before subtraction in PEMDAS.

g(3) = 12 - 9

Lastly, we can subtract 9 from 12 to get the final value.

g(3) = 3   So, the value for g(x) when x = 3 is 3.

Now, we'll solve for g(x) when x = 5.

The first step is to change wherever it says x in the equation to 5, because that is the value we are solving for.

g(5) = 4(5) - 9

Next, we can multiply 4 by 5, because multiplication comes before subtraction in PEMDAS.

g(5) = 20 - 9

Lastly, we can subtract 9 from 20 to get the final value.

g(5) = 11   So, the value for g(x) when x = 5 is 11.

Hope this helps!

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.