You have also set up a card game in which a player picks a card from a standard deck of 52 cards. the player wins if these two events occur together: e1, in which the card drawn is a black card, and e2, in which the card drawn is a numbered card, 2 through 10.what is the probability of getting a black card and a numbered card? calculate the probabilities p(e1) and p(e2) as fractions.

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

EDMENTUM / PLATO ANSWER

CAN JUST WRITE:

=  (50%)

=  (69.2%) :)))))

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: