Avi's pet hamster chubby loves to run in his hamster wheel. during one "race", avi counts 100100100 rotations of the wheel. she wants to know how far chubby ran, so she measures the diameter of the wheel and finds that it is 20 \text{ cm}20 cm20, space, c, m. how far did chubby run? round your answer to the nearest \text{cm}cmc, m.

6280 cm

Step-by-step explanation:

Given: The diameter of hamster wheel = 20 cm

The circumference of hamster wheel is given by :-

, where d is the diameter of the hamster wheel.

During one race, the number of rotations of the wheel = 100

Therefore, the distance run by chubby is given by :-

6283 cm.

Step-by-step explanation:

We have been given that Avi's pet hamster Chubby completed 100 rotations of the wheel. The diameter of the hamster wheel is 20 cm.

Since wheel is a circle, so the distance covered by Chubby in one rotation will be equal to the circumference of wheel.

, where,

r = Radius of circle,

D = Diameter of circle.

Now we will find the circumference of wheel by substituting in above formula.

Since Chubby covers a distance of 62.83185307 cm in one rotation, so in 100 rotations distance covered by Chubby would be:

Therefore, Chubby ran a distance of 6283 centimeters.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: