Last year a man earned 19,200. this year his salary increased to 20,736. what was the percent of his increase ? show all steps

Last year a man earned 19,200. This year his salary increased to 20,736. What was the percent of his increase ?

Solution

Here we have to use the formula.

Percentage of increase =

Increase in earning = 20, 736 - 19,200 = $1536

Original number = 19,200

Now plugin these values into the formula, we get

Percentage of increase = %

The answer is 8%

Hope you will understand the steps.

Thank you. :)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.