G(x)=(x^2+1)(3x-5) what is the value of g(4)?

g(x) = x^2 + 1(3x - 5)

Replace all x's with 4.

g(4) = 4^2 + 1(3 * 4 - 5)

g(4) = 16 + 1(12 - 5)

g(4) = 17(7)

g(4) = 119 (This is your answer.)

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step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)