Which ordered pair makes both inequalities true? y > –3x + 3 y > 2x – 2 (1,0) (–1,1) (2,2) (0,3)

All options are wrong.

Step-by-step explanation:

We have y > –3x + 3 and y > 2x – 2

Option A - (1,0)

          y > –3 x 1 + 3 = 0

         We have y = 0, which is not greater than 0.

         Option A is not correct.        

Option B - (–1,1)

          y > –3 x -1 + 3 = 6

         We have y = 1, which is not greater than 6.

         Option B is not correct.

Option C - (2,2)

          y > –3 x 2 + 3 = -3

         We have y = 2, which is greater than -3.

          y > 2 x 2 – 2  = 2

         We have y = 2, which is not greater than 2.

         Option C is not correct.  

Option D - (0,3)

          y > –3 x 0 + 3 = 3

         We have y = 3, which is not greater than 3.

         Option D is not correct.    

All options are wrong.

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step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10