Simplify 35x^3y^5/7x^2y^4 show work mark brainliest only answer if you know how to do laws of exponents

When you write expressions like this, you need to pay attention to the Order of Operations. As this is written, the only factor in the denominator is the one immediately after the division symbol: 7. This simplifies to

... (35/7)·x^(3+2)·y^(5+4) = 5x^5y^9

We suspect you might intend ...

... (35x^3y^5)/(7x^2y^4) = (35/7)x^(3-2)y^(5-4) = 5xy

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x