Aline passes through the given points. write an equation for the line in point-slope form. then rewrite the equation in slope intercept form. #1 (-2, 6) (5, 1) #2 (3, -8) (-2, 5) #3 (1, 1/2) (3, 2)

#1 first we need to solve for slope which is y2-y1/x2-x1

plug in the coordinates and get 1-6/5-(-2) which makes our slope -5/7

then use the equation for point slope form which is:

y-y1=m(x-x1)

then plug in one of the coordinates, I'll use (-2,6), now we have

y-6=-5/7(x+2)

now to make this slope intercept, we just have to solve

y-6=-5/7x-10/7

y=-5/7x+4 4/7

repeat all these steps for 2 and 3

#2: slope = -13/5

plug it in to point slope and get: y+8=-13/5(x-3)

slope intercept:

y+8= -13/5x + 39/5

y= -13/5x -1/5

#3: slope = 3/4

point slope form: y-2=3/4(x-3)

slope intercept: y-2=3/4x-9/4 --> y=3/4x-1/4

b) well because you get well

if you need just tell me and i will come to the rescue.

step-by-step explanation: