Keisha has a total of $6000 to invest in two accounts for 1 year. one account pays 5% simple interest and the other pays 6% simple interest. how much should she invest in each account so that the total interest earned is $335?

He invest $2500 in account with rate of interest 5% and invest $3500 in account with 6% of interest so that the total interest earned is $335.

Step-by-step explanation:

Given: The rate of interest for account 1= 5%=0.05

The rate of  interest for account 2= 6%=0.06

Let P be the Principal amount Keisha invested in the account with 5% interest .

Then the amount she will invest in account with 6% interest= 6000-P

Time = 1 year

The simple interest is given by:-

Simple interest for account 1=

Simple interest for account 2=

According to the question,

Total Interest =$335

So, he invest in account with 5% interest= $2500

He invest in account with 6 % interest=$6000-$2500=$3500

answer: our required factorization will be

(3x+4)(x²-5)

step-by-step explanation:

since we have given that

now, we will write it as :

so, we get

5(3x+4)

similarly,

here, we get,

2(3x+4)

together it becomes,

hence, our required factorization will be

(3x+4)(x²-5)