Mary pitches a ball. the initial height is 4 ft and velocity 55 ft per second. when will the ball hit the ground?

t = 3.5 sec

Step-by-step explanation:

The equation that represents the position of the ball as a function of time is the following:

Where:

= Initial position of the ball (4 feet tall)

= Initial speed of the ball (55feet / s)

a = acceleration (9.8 , or in this case 32.16)

t = time in seconds

Then we want to know how long it takes to get to the ground, for this we equal h (t) = 0 and clear t.

So:

Solving the second degree equation we have:

t = -0.071 sec

t = 3.5 sec

We must take the positive solution.

So:

t = 3.5 sec

boxplot e is the answer

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point