Mary pitches a ball. the initial height is 4 ft and velocity 55 ft per second. when will the ball hit the ground?

t = 3.5 sec

Step-by-step explanation:

The equation that represents the position of the ball as a function of time is the following:

Where:

= Initial position of the ball (4 feet tall)

= Initial speed of the ball (55feet / s)

a = acceleration (9.8 , or in this case 32.16)

t = time in seconds

Then we want to know how long it takes to get to the ground, for this we equal h (t) = 0 and clear t.

So:

Solving the second degree equation we have:

t = -0.071 sec

t = 3.5 sec

We must take the positive solution.

So:

t = 3.5 sec

c

step-by-step explanation:

at least i think its

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )