Train a leaves westtown and travels at 50 mph toward smithville, 330 miles away. at the same time, train b leaves smithville and travels at 60 mph toward westtown. after how many hours do the two trains meet? enter your answer in the box.

Hello mate!

first, let's do a list with all the things we know about this problem:

Both trains depart at the same time; we can define this time as t = 0 in hours.

the velocity of train A is 50mph

the velocity of train B is 60mph

both trains travel in opposite directions.

the initial distance between both trains is equal to 330 miles:

we want to know when the trains will meet each other:

The trains will meet each other when the sum of their traveled distance is equal to the initial separation between them.

the distance traveled by the train A is equal to his velocity multiplied by the time that passed since it departed.

this is: Da(t) = (50*t)mi

and the distance for the train B is: Db(t) = (60*t)mi

then, as we know, the trains will meet when Da(t) + Db(t) = 330mi

then 50*t + 60*t = 330

110*t = 330

t = 330/110 = 3h

the trains will meet 3 hours after they departed.

i think it would be c

mark brainliest if im right

step-by-step explanation: