The ones with circles are the ones i need to do

1. for (0,0) that would be at the very bottom at 0 is where you're point will be.

on (1,4) go over to the right to 1 nd then go up right below 5 and make a point.

for (2,8) go to the right to 2 and then move up to 8 and make a point.

for (3,12) go to the right 3 and then go up to 12 and make a point.

2. It makes a line.

3. (1,5)           (2,10)        (3,15)        (4,20)

chart on left is right but put parenthesis on both side like that ^

4. For Kens go to the right to 1 and go up to 5 and put a point. then go to 2 to the right and 10 up make point. then go 3 to right and 15 up and make a point. then go 4 to right and up 20 and make a point. Do same with other chart.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.