Find two consecutive even integers such that the sum of the larger and three times the smaller is 234

Represent even numbers as "2n" since each is a multiple of 2.

Represent odd numbers as "2n+1" since each is one more than an even.

Your problem:

smaller # : 2n

larger #: 2n+2

EQUATION:

2n+2 + 3(2n) = 234

8n = 232

n = 29

smaller = 2*29 = 58

larger = 2n+2 = 60

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

college