Graph the line using a point and a slope. write the equation of each line. a line that contains point (0, −3) and perpendicular to another line whose slope is 2.

The line passes through (0, -3)

Its perpendicular to another line whose slope is 2

The slope of the line therefore is -1/2 = -0.5 (the product of slopes two perpendicular lines is -1)

Taking another point (x,y) on the line;

Slope = change in y-axis ÷ change in x-axis

-0.5 = (y - -3) / (x - 0)

y = -0.5x - 3

y=-0.5x-3

Hope this helps!

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts