Given the trigonometric equation: find 3 positive solutions. explain how you found the solution : -)

The sine function is negative only in Quadrants III and IV.  The radius would be 2 and the opposite side would be -√3.  A similar triangle in the first Quadrant would have the central angle 60 degrees; note that sin 60 = opp/hyp √3 / 2.   Thus, one representation of the given sin y = -√3/2 would be (180 + 60) degrees, or +240 degrees.  Check for yourself that sin 240 degrees = -√3/2.

Another would be (360 - 60) degrees, or 300 degrees.  Note that sin 300 degrees = -√3/2.  

A third would be (300 + 360) degrees, or 660 degrees.  Verify that sin 660 = -√3 / 2.

Three positive angles whose sines are all -√3/2 are {240, 300, 660}.

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function