2. you have just signed an annual contract with telus for a cell phone. the base rate is $22 per month and $0.44 per minute. there are no free minutes included with this contract. a) write a linear equation in which y represents the total cost for the cell phone per month and x represents the number of minutes spend on the phone each month.

As per the contract the base rate of the connection is $22.00 per month and calling rate through that phone is $0.44 per minute.

Here, represents the total cost for the cell phone per month and represents the number of minutes spend on the phone call each month.

Now, if we have spent minutes over the phone call over the period of a month, then the total cost we need to pay for the phone calls is given by:

, since it costs $0.44 for each minute of phone call.

And in addition to the cost of phone calls he needs to pay a base rate of $22.00.

So, the linear equation that represents the total cost is given by:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

the correct answer is

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