Order the steps to solve the equation log3(x + 2) = log3(2x^2 − 1) from 1 to 6. 0 = (2x − 3)(x + 1) 0 = 2x^2 − x −3 potential solutions are −1 and 3/2 2x − 3 = 0 or x + 1 = 0 x + 2 = 2x^2 − 1 3^log3(x + 2) = 3^log3(2x2 − 1)

Consider the equation

1 step (option 6): rise 3 to the power of left and right sides

Thus, you get equation from option 5.

2 step (option 2): rewrite the equation in one side

3 step (option 1): factor the previous equation

Then the equatios becomes

4 step (option 4): If product is equal to zero, then either or

5 step (option 3): Then Potential solutions are −1 and 3/2. You can check them substituting into the initial equation:

for

for

Both are roots.

correct order of steps is 6, 5, 2, 1, 4, 3.