Aconjecture and the paragraph proof used to prove the conjecture are shown. drag an expression or statement to each box to complete the proof. it is given that e is the midpoint of so, ≅ by the definition of midpoint. therefore, de=ef by the de+ef=df by the and so de+de= by substitution. simplifying gives 2de=df . answer choices: segment congruence segment addition df ef df de

Observe the figure given.

Let us complete the given paragraph:

It is given that E is the midpoint of DF. So, DE by the definition of midpoint.

As, midpoint divides the line segment into two equal halves.

Therefore, DE  =EF by the segment congruence postulate. DE+EF = DF by the segment addition postulate and so DE+DE = DF by substitution.

Segment Addition Postulate states that given 2 points P and Q, a third point S lies on the line segment PQ if and only if the distances between the points satisfy the equation PS + SQ = PQ.

Simplifying gives 2DE = DF.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

i honestly dont know