Consider the parabola r(t)equalsleft angle at squared plus 1 comma t right angle, for minusinfinityless thantless thaninfinity, where a is a positive real number. find all points on the parabola at which r and bold r prime are orthogonal.

Given:-    ; , where a is any positive real number.

Consider the helix parabolic equation :  

now, take the derivatives we get;

As, we know that two vectors are orthogonal if their dot product is zero.

Here,    are orthogonal i.e,   

Therefore, we have ,

take t common in above equation we get,

⇒ or

To find the solution for t;

take

The number determined from the coefficients of the equation

The determinant

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola   i.e <1,0>

i think the answer would be c

below

step-by-step explanation:

1. 5/1

2. 10/16

3. 90/2

4. 1/20

5. 3/1

6. 14/24

7. 1/4

8. 18/10