Whats the axis of symmentry for f(x)=-2(x-2)squared-4

f(x)=-2(x-2)squared-4 => f(x)=-2(x-2)^2 - 4  =>  2(x^2-4x+4) - 4

This becomes f(x) = 2x^2 - 8x + 8 - 4.

This being a quadratic, a = 2, b = -8 and c = 4.

Theformula for the axis of symmetry is x = -b/(2a).  Here, that comes to:

x = -(-8) / (2*2) = 8/4 = 2

The axis of symmetry here is the vertical line x = 2.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

60

step-by-step explanation:

every triangle measures a total of 120 degrees. you have to find angle c. we know that isosceles triangles angles are equal. 60 degrees plus 60 degrees gives you 120.