Find the value of tan θ for the angle shown. (2 points)a) tan θ = negative square root of thirty-three divided by four b) tan θ = negative four times square root of thirty-three divided by thirty-three c) tan θ = negative four-sevenths d) tan θ = negative square root of thirty-three divided by seven

square root (33) = 5.7445626465

arc tan (5.7445626465 / -4) =

arc tan (-1.4361406616) = -55.15

360 -55.15 = 304.85 degrees

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130