What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 1/3 ? y+6=1/3(x+2) y+2=1/3(x+6) y−2=1/3(x−6) y−6=1/3(x−2)

y + 6 = (x + 2)

The equation of a line in ' point-slope form ' is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

here m = and (a , b ) = ( - 2, - 6)

y + 6 = (x + 2) → equation in point- slope form

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

idk

step-by-step explanation:

idk