Write an equation of a line that is perpendicular to y=-0.3+6 that passes through the point (3,-8)

y= 10/3 x -18

Step-by-step explanation:

Perpendicular lines meet the following condition:

m2*m1=-1 (1)

The product of their slope is -1.

From the equation of the first line we can obtain the first slope.

y=-0.3x+6 -> m1=-0.3

Hence, the slope of our desired line is obtained from equation (1).

m2=10/3.

Remember, the equation of a line is given by:

y=mx+b

Now, we need to find the term 'b' and we will do that by evaluating the point (3,-8).

-8=10/3 * 3 +b.

b=-18.

Finally, our desired line has the following equation:

y= 10/3 x -18

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol