To the nearest ten thousand, the population of vermont was est ikmated to be about 620,000 in 2008. what might have been the exact populationof vermont in 2008?

To the nearest ten thousand, the population of Vermont was estimated to be about 620,000 in 2008.

This means 624999 is the highest population that can be rounded off to 620000 ; to the nearest ten thousand.

And 620001 is the smallest number that can be rounded to 620000.

Hence, the population must have been between 620001 to 624999.

a

b

d

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204