How large is the acceleration of a 60 kg runner if the friction between her shoes and the pavement is 500 n?

The force of friction is given in the scenario:

Force = 500 Newton

and the mass of the runner  is 60 kg

To find the acceleration we need to use the relation between force, mass, and the acceleration of the object:

Where 'F' represents the force, 'm' represents the mass, and 'a' represents the acceleration.

Plugging the value of variables we get:

Solving for 'a' (acceleration) we get:

Newton/kilogram or meters/ second squared

So the acceleration of the runner is 8.33 meters/ second squared.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse