Arooms floor is y meters long. it’s width is 5 meters shorter. if the perimeter of the floor is (4y + 1) meters, can you solve for its length?

The question says that the length of the floor of a room is 'y' meters.

Its width is 5 meters shorter than the length,

If the width is 5 meters shorter than the actual width should be:

meters

Now the room is in the shape of a rectangle, so we will use the formula of the perimeter of a rectangle:

Perimeter =

The length of the floor is 'y' meters

The width of the floor is 'y-5' meters

Plugging the values of length and width we get,

Question says that the perimeter of the rectangle is meters.

So,

We will solve for 'y'.

Since,

The system of equation seems to have no solution.

Hence, no such floor exists.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: