Write the equation of a line that is perpendicular to y=5 and that passes through the point (-7,-5)

Given line : y = 5

=> y = 0×x + 5

Comparing it with y = mx + c

slope of line, m = 0
Thus, this line is parallel to x axis.
A line perpendicular to it will be parallel to y axis.

So the perpendicular line will be of the form: x = k

where k is a constant.

It passes through (-7,-5)

Thus

x = k

=> -7 = k

=> k = -7

Thus, equation of perpendicular line is x = -7

Just a second zzz