Look at the picture. what is the solution worth 10 points

The coordinates of the point intersection of lines (-1, -1)

If you want solve:

y = -2x - 3, y = 3x + 2

-2x - 3 = 3x + 2     |+3

-2x = 3x + 5     |-3x

-5x = 5     |:(-5)

x = -1

Put the value of x to the first equation:

y = (-2)(-1) - 3 = 2 - 3 = -1

x = -1, y = -1

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation: