The denarius was a unit of currency in ancient rome. suppose it costs the roman government 1 0 1010 denarius per day to support 3 33 legionaries and 3 .33 archers. it only costs 3.33 denarius per day to support one legionary and one archer. use a system of linear equations in two variables. can we solve for a unique cost for each soldier?

assuming you copied and pasted this from khan academy and the original numbers are 10, 3, 3 and 3, make two equations:

x+y=3 and 3x+3y=10

x+y=3 -> solve for y -> y=-x+3

plug into 3x+3y=10

3x+3(-x+3)=10

3x-3x+9=10 -> the 3x's cancel out

9=10

however 9 does not equal 10 and therefore, there is no solution

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet