Michael has a box of colored balls. it contains four red balls, two green balls, and five blue balls. michael draws a ball at random from the box let r denote the event that the ball he draws is red, and let b denote the event that the ball he draws is blue. what is pr(r|b)? what is pr(r|b′)? enter your answers as whole numbers or fractions in lowest terms.

The probability allows finding that the probability for a red ball is 0.36 and the probability of finding a red ball is 0.45

data parameters

* number of balls of each color

to find

* the probability of each color

Probability is a measure of the certainty that a specific ball will come out. To find the probability we must have the number of events between the total number of events.

In this case the total number of events is the number of existing balls

        N = ∑ n_i

where N is the total number of events (balls) and n_i is the number of balls of each type

Probability can be written

         Pr (R) =  n_i /N

For the case presented, the total number of events is

        N = 4 + 2 + 5

        N = 11

applying the probability formula

therefore the probability of finding a red ball is

        Pr (R) = 4/11 = 0.36

The green

         Pr (G) = 2/11 = 0.18

for the blue ball

         Pr (B) = 5 /11=0.45

Consequently the probability  of finding a red ball is 0.36 and the probability of finding a blue ball is 0.45

to learn more about probability Here:  link

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

after going and makeing graphs i would go with a,

there is nothing that is matches the graph. if there was i would show you. but therefore my answer is a.

hope i

-lavira: )