Astudent theater charges $9.50 per ticket. a. the theater has already sold 70 tickets. identify an inequality that represents how many more tickets xx the theater needs to sell to earn at least $1000. 70+9.50x≥100070+9.50x≥1000 (9.50)(70)+x≥1000(9.50)(70)+x≥1000 9.50(70+x)≥10009.50(70+x)≥1000 1000≥(9.50)(70)+9.50x1000≥(9.50)(70 )+9.50x question 2 solve the inequality.

Answer-

The inequality equation for the given problem is "9.50(70+x) ≥ 1000"

And the theater need to sell 36 more tickets in order to get at least $1000.

Solution-

Let's assume x is the number of more tickets to sell in order to get at least  $1000  and the price of one ticket is $9.50.

No. of tickets already sold by the theater = 70

So total earnings till now = $(70 × 9.50)

Total earnings by selling x tickets = $(x × 9.50)

∴ Hence, the inequality equation is,

 ( ∵ since tickets can only be sold as whole)

∴ So, the theater need to sell 36 more tickets in order to get at least $1000.