Mathematics, 09.07.2019 13:00 Jasten
−5x + 1 ≥ x − 5 4x − 5(x + 1) ≤ 2 −3(x − 1) > 4 6(x + 3) − 2 ≤ 4x 5(x + 1) ≥ 3x + 4 can you guys me with this for free cookiesxdxd
Answers: 1
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−5x + 1 ≥ x − 5 4x − 5(x + 1) ≤ 2 −3(x − 1) > 4 6(x + 3) − 2 ≤ 4x 5(x + 1) ≥ 3x + 4 can you guys...
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