Two cyclists, 80 miles apart, start riding toward each other at the same time. one cycles 3 times as fast as the other. if they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

The speed of the faster cyclist will be 30 miles/hour.

Explanation

One cyclist is 3 times as fast as the other.

Lets assume that the speed of the slower cyclist is   miles/hour.

So, the speed of the faster cyclist will be:   miles/hour.

They start riding toward each other at the same time and meet 2 hours later.

We know that,  

So, the distance traveled by slower cyclist in 2 hours miles and the distance traveled by faster cyclist miles.

Given that, they were 80 miles apart at the starting. So, the equation will be.....

So, the speed of the faster cyclist will be: (3×10)= 30 miles/hour.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!