Lkm= 7x-5 nkm= 3x +9 find the angle to lkm

The measure of the angle m<LKM is 156degrees

The point where two lines meet is called angle.

From the diagram shown:

m<LKN + m<NKM = m<LKM and:

m<LKN = m<NKM

Hence m<NKM + m<NKM = m<LKM

2m<NKM = m<LKM

2(3x+9) = 7x-5

6x+18 = 7x - 5

6x-7x = -5-18

-x = -23

x = 23

Get the angle m<LKM

m<LKM = 2m<NKM

m<LKM = 2 (3x+9)

m<LKM = 6x+18

m<LKM = 6(23) + 18

m<LKM =  138+18

m<LKM = 156degrees

Hence the measure of m<LKM is 156 degrees

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Given =

∠lkm = 7x - 5

∠nkm = 3x +9

find = value of∠ lkm.

To proof -  let us assume that we takeapoint say n and draw a line nk.

                nk is angle bisector it divided angle in two equal parts.

( as shown in the diagram given below)

thus we have

∠lkm = ∠lkn + ∠nkm

7x-5 = 3x+9 +3x +9

x = 23

thus the value of∠ lkm

∠lkm = 7x-5  

(put the value of x)

thus

∠lkm = 7×23 - 5

∠lkm = 156°