Jason mixed 8 ml of a salt solution with 11ml of a 47% salt solution, to make a 43% salt solution. find the percent salt concentration of the first solution

Let x% be the salt concentration of first solution.

Then in 8ml, amount of salt =  

Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.

amount of salt in 11ml of 47% salt solution is  =  

So, total amount of salt in new mixture =  

But given that this new solution is a 43% salt solution.

Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is

Hence  

            8x+517 = 817

             8x=817-517 = 300

             x= 300/8 = 37.5

Hence the salt concentration in the first solution is 37.5%

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step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v