Grade 9 math algebra 1 variables & expressions can anyone me with this question? write an expression and then evaluate when x = -6. nine subtracted from the quotient of twice a number, x, and three. ? evaluate when x = -6 ?

We have to determine the expression for the statement:

"Nine subtracted from the quotient of twice a number, x, and three"

Expression is

We have to evaluate the value of the given expression at x = -6

=

=

=

= -13

So, the value of the expression is -13.

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places